GSEB Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.4

   

Gujarat Board GSEB Textbook Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 Textbook Questions and Answers.

Gujarat Board Textbook Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.4

Question 1.
Construct the following quadrilaterals.
(i) Quadrilateral
DEAR
DE = 4 cm
EA = 5 cm
AR = 4.5 cm
∠E = 60°
∠A = 90°

GSEB Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.4

(ii) Quadrilateral
TRUE
TR = 3.5 cm
RU = 3 cm
UE = 4 cm
∠R = 75°
∠U= 120°
Solution:
(i) Steps of construction:
I. Draw a line segment DE = 4 cm.
II. At E, draw \(\overrightarrow { EX } \) such that ∠DEX = 60°.
III. From \(\overrightarrow { EX } \), cut-off EA = 5 cm.
IV. At A, draw ray \(\overrightarrow { AY } \) such that ∠EAY = 90°.
V. From \(\overrightarrow { EY } \), cut-off AR = 4.5 cm.
VI. Join R and D.
GSEB Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 ima-1
Thus, DEAR is the required quadrilateral.

GSEB Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.4

(ii) Steps of construction:
GSEB Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 ima-2
I. Draw a line segment \(\overrightarrow { TR } \) =3.5 cm.
II. At R, draw a ray \(\overrightarrow { RX } \) such that ∠TRX = 15°.
III. From \(\overrightarrow { RX } \) , cut-off RU = 3 cm.
IV. At U, draw \(\overrightarrow { UY } \) such that ∠RUY = 120°
V From UY, cut-off \(\overrightarrow { UE } \) = 4 cm.
VI. Join E and T.
Thus, TRUE is the required quadrilateral.

GSEB Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.4

Leave a Comment

Your email address will not be published. Required fields are marked *