# GSEB Solutions Class 7 Maths Chapter 5 Lines and Angles InText Questions

Gujarat BoardĀ GSEB Textbook Solutions Class 7 Maths Chapter 5 Lines and Angles InText Questions and Answers.

## Gujarat Board Textbook Solutions Class 7 Maths Chapter 5 Lines and Angles InText Questions

Try These (Page 94)

Question 1.
List ten figures around you and identify the acute, obtuse and right angles found in them.
Solution:
It is an activity. Please do it yourself.

Think, Discuss and write (Page 95)

Question 1.
Can two acute angles be complement to each other?
Solution:
Yes.
For example, 30Ā° is an acute angle and 60Ā° is also an acute angle.
Since, 30Ā° + 60Ā° = 90Ā°
ā“ 30Ā° and 60Ā° are complementary angles, i.e. two acute angles can be complement to each other.

Question 2.
Can two obtuse angles be complement to each other?
Solution:
No.
An obtuse angle has its measure greater than 90Ā°. Therefore, sum of two obtuse angles cannot be equal to 90Ā°, i.e. they cannot be complement to each other.

Question 3.
Can two right angles be complement to each other?
Solution:
No.
1 right angle = 90Ā°
Therefore, two right angles cannot be complement to each other.

Try These (page 95)

Question 1.
Which pairs of following angles are complementary?

(i) Since 70Ā° + 20Ā° = 90Ā°
ā“ Angles 70Ā° and 20Ā° are complementary.

(ii) āµ 75Ā° + 25Ā° = 100Ā° and 100Ā° ā  90Ā°
ā“ Angles 75Ā° and 25Ā° are not complementary.

(iii) āµ 48Ā° + 52Ā° = 100Ā° and 100Ā° ā  90Ā°
ā“ The angles 48Ā° and 52Ā° are not complementary.

(iv) āµ 35Ā° + 55Ā° = 90Ā°
ā“ The angles 35Ā° and 55Ā° are complementary.

Question 2.
What is the measure of the complement of each of the following angles?
(i) 45Ā°
(ii) 65Ā°
(iii) 41Ā°
(iv) 54Ā°
Solution:
(i) Let the complement of 45Ā° be x.
ā“ x + 45Ā° = 90Ā° or x = 90Ā° – 45Ā° = 45Ā°
ā“ Complement of 45Ā° is 45Ā°.

(ii) Let the complement of 65Ā° be p.
ā“ p + 65Ā° = 90Ā° or p = 90Ā° – 65Ā° = 25Ā°
ā“ The complement of 65Ā° is 25Ā°.

(iii) Let the complement of 41Ā° be m.
ā“ m + 41Ā° = 90Ā°
or m = 90Ā° – 41Ā°
or m = 49Ā°
Thus, the complement of 41Ā° is 49Ā°.

(iv) Let the complement of 54Ā° be y.
ā“ y + 54Ā° = 90Ā° or y = 90Ā° – 54Ā° = 36Ā°
Thus, the complement of 54Ā° is 36Ā°.

Question 3.
The difference in the measures of two complementary angles is 12Ā°. Find the measures of the angles.
Solution:
Let one of the angles be x.
āµ Their difference = 12Ā°
ā“ The other angle = x + 12Ā°
Since, the sum of the measures of two complementary angles is 90Ā°.
ā“ x + (x + 12Ā°) = 90Ā°
or 2x = 90Ā° – 12Ā°
or 2x = 78Ā°
Dividing both sides by 2, we have
$$\frac { 2x }{ 2 }$$ = $$\frac { 78Ā° }{ 2 }$$ or x = 39Ā°
ā“ One angle =39Ā°
And the other angle = 39Ā° + 12Ā° = 51Ā°

Think, Discuss and Write (Page 96)

Question 1.
Can two obtuse angles be supplementary?
Solution:
No.
The measure of an obtuse angle is more than 90Ā°.
The sum of two angles, (each more than 90Ā°), is more than 180Ā°.
Thus, two obtuse angles cannot be supplementary.

Question 2.
Can two acute angles be supplementary?
Solution:
No.
The measure of an acute angle is less than 90Ā°.
Therefore, the sum of two acute angles is less than 180Ā°.
ā“ Two acute angles cannot be supplementary.

Question 3.
Can two right angles be supplementary?
Solution:
Yes.
The measure of a right angle is 90Ā°.
ā“ The sum of two right angles = 180Ā°
i.e. the two right angles are supplementary.

Try These (Page 96)

Question 1.
Find the pairs of supplementary angles in the following figures:

Solution:
(i) Measures of the given angles are 110Ā° and 50Ā°.
āµ 110Ā° + 50Ā° = 160Ā° and 160Ā° ā  180Ā°
ā“ 110Ā° and 50Ā° are not a pair of supplementary angles.

(ii) Measures of the given angles are 105Ā° and 65Ā°.
āµ 105Ā° + 65Ā° = 170Ā° and 170Ā° ā  180Ā°
ā“ 105Ā° and 65Ā° are not a pair of supplementary angles.

(iii) Measures of the given angles are 50Ā° and 130Ā°.
āµ 50Ā° + 130Ā° = 180Ā°
ā“ 50Ā° and 130Ā° are a pair of supplementary angles.

(iv) Measures of the given angles are 45Ā° and 45Ā°.
āµ 45Ā° + 45Ā° = 90Ā° and 90Ā° ā  180Ā°
ā“ 45Ā° and 45Ā° are not a pair of supplementary angles.

Question 2.
What will be the measure of the supplement of each one of the following angles?
(i) 100Ā°
(ii) 90Ā°
(iii) 55Ā°
(iv) 125Ā°
Solution:
(i) Let the supplement of 100Ā° be x.
ā“ 100Ā° + x = 180Ā°
or x =180Ā° – 100Ā° = 80Ā°
The measure of the supplement of 100Ā° is 80Ā°.

(ii) Let the supplement of 90Ā° be x.
ā“ x + 90Ā° = 180Ā°
or x =180Ā° – 90Ā° = 90Ā°
ā“ The measure of the supplement of 90Ā° is 90Ā°.

(iii) Let the supplement of 55Ā° be m.
ā“ 55Ā° + m = 180Ā°
or m = 180Ā° – 55Ā°
or m = 125Ā°
ā“ The supplement of 55Ā° is 125Ā°.

(iv) Let the supplement of 125Ā° be y.
ā“ y + 125Ā° = 180Ā°
or y = 180Ā° – 125Ā°
or y = 55Ā°
ā“ The supplement of 125Ā° is 55Ā°.

Question 3.
Among two supplementary angles the measure of the larger angle is 44Ā° more than the measure of the smaller. Find their measures.
Solution:
Let the smaller angle be x.
ā“ The measure of the larger angle = (x + 44Ā°)
Since, the two angles are supplementary
ā“ x + (x + 44Ā°) = 180Ā°
or 2x + 44Ā° =180Ā°
or 2x = 180Ā° – 44Ā°
or 2x = 136Ā°
or x = $$\frac { 136Ā° }{ 2 }$$
ā“ The smaller angle = 68Ā°
Larger angle = 68Ā° + 44Ā° = 112Ā°

Try These (Page 97)

Question 1.
Are the angles marked 1 and 2 adjacent? If they are not adjacent, say, āwhyā.

Solution:
(i) Yes, ā 1 and ā 2 are adjacent angles.
(ii) Yes, ā 1 and ā 2 are adjacent angles.
(iii) No, ā 1 and ā 2 are not adjacent angles because they have no common vertex.
(iv) No, ā 1 and ā 2 are not adjacent angles because ā 1 is a part of ā 2.
(v) Yes, ā 1 and ā 2 are adjacent angles.

Question 2.
In the given figure, are the following adjacent angles?

(a) ā AOB and ā BOC
(b) ā BOD and ā BOC Justify your answer.
Solution:
(a) Yes, ā AOB and ā BOC are adjacent angles, because they have common vertex O and their outer arms (OA and OC) are on either side
of the common arm OB.
(b) No, because ā BOC is a part of ā BOD.

Think, Discuss and Write (Page 98)

Question 1.
Can two adjacent angles be supplementary?
Solution:

Yes, in the adjoining figure, ā AOB and ā BOC are adjacent angles.
Also, ā AOB + ā BOC = 180Ā°
ā“ ā AOB and ā BOC are supplementary.

Question 2.
Can two adjacent angles be complementary?
Solution:
Yes, in the figure, ā PQR and ā RQS are adjacent angles,
Also ā PQR + ā RQS = 90Ā°
i.e. ā PQR and ā RQS are complementary angles.

Question 3.
Can two obtuse angles be adjacent angles?
Solution:
Yes, in the figure, ā BOC and ā COD are obtuse angles and they are adjacent angles.

Question 4.
Can an acute angle be adjacent to an obtuse angle?
Solution:
Yes, in the figure, ā 1 and ā 2 are adjacent angles. ā 1 is acute and ā 2 is an obtuse angle.

Think, Discuss and Write (Page 99)

Question 1.
Can two acute angles form a linear pair?
Solution:
No. The sum of the measures of two acute angles is less than 180Ā° because measures of each acute angle is less than 90Ā°.

Question 2.
Can two obtuse angles form a linear pair?
Solution:
No. The sum of the measures of two obtuse angles is more than 180Ā°.

Question 3.
Can two right angles form a linear pair?
Solution:
Yes, because the sum of two right angles is 180Ā°.

Try These (Page 99)

Question 1.
Check which of the following pairs of angles form a linear pair.

Solution:
(i) Yes.
āµ 140Ā° + 40Ā° = 180Ā°
ā“ The given pair of angles forms a linear pair.

(ii) No.
āµ 60Ā° + 90Ā° = 150Ā° and 150Ā° ā  180Ā°
ā“ The given pair of angles does not form a linear pair.

(iii) No.
āµ 90Ā° + 80Ā° = 170Ā° and 170Ā° ā  180Ā°
ā“ The given pair of angles does not form a linear pair.

(iv) Yes.
āµ 115Ā° + 65Ā° = 180Ā°
ā“ The given pair of angles forms a linear pair.

Try These (Page 101)

Question 1.
In the given figure, if ā 1 = 30Ā°, find ā 2 and ā 3.
Solution:

āµ ā 3 and ā 1 are vertically opposite angles,
ā 3 = ā 1
But ā 1 = 30Ā° [Given]
ā“ ā 3 = 30Ā°
Again, ā 3 and ā 2 form a linear pair.
ā“ ā 3 + ā 2 = 180Ā° or 30Ā° + ā 2 = 180Ā°
or ā 2 = 180Ā° – 30Ā° = 150Ā°
Thus, ā 2 = 150Ā°
and ā 3 = 30Ā°

Question 2.
Give an example for vertically opposite angles in your surroundings.
Solution:
Please do it yourself.

Think, Discuss and Write (Page 104)

Question 1.
In the figure, AC and BE intersect at P. AC and BC intersect at C, AC and EC intersect at C. Try to find another ten pairs of intersecting line segments.

Solution:
Various pairs of intersecting lines are:
(i) Intersecting at B are:
[CB and EB], [PB and CB]

(ii) Intersecting at C are:
[BC and EC], [PC and BC], [PC and EC] ‘

(iii) Intersecting at E are:
[BE and CE], [PE and CE]

(iv) Intersecting at P are:
[BP and CP], [EP and CP],

(v) [AP and BP] and [AP and EP]

Question 2.
Can two lines intersect in more than one point? Think about it.
Solution:
No, two lines cannot intersect in more than one point.

Try These (Page 104)

Question 1.
Find examples from your surroundings where lines intersect at right angles.
Solution:
Please do it yourself.

Question 2.
Find the measure of the angles made by the intersecting lines at the vertices of an equilateral triangle.
Solution:

Points of intersection are A, B and C.
Measure of ā A = 60Ā°
Measure of ā B = 60Ā°
Measure of ā C = 60Ā°

Question 3.
Draw any rectangle and find the measures of angles at the four vertices made by the intersecting lines.
Solution:

Measure of ā A = 90Ā°
Measure of ā B = 90Ā°
Measure of ā C = 90Ā°
Measure of ā D = 90Ā°

Question 4.
If two lines intersect, do they always intersect at right angles?
Solution:
No.

Try These (Page 105)

Question 1.
Suppose two lines are given. How many transversals can you draw for these lines?
Solution:
We can draw an infinite number of transversals to two given lines.

Question 2.
If a line is a transversal to three lines, how many points of intersections are there?
Solution:
As shown in the adjoining figure, there are 3 distinct points of intersection.

Question 3.
Try to identify a few transversals in your surroundings.
Solution:
Please do it yourself.

Try These (Page 106)

Question 1.
Name the pairs of angles in each figure:

Solution:
In the figures,
(i) ā 1 and ā 2 are a pair of corresponding angles.
(ii) ā 3 and ā 4 are a pair of alternate interior angles.
(iii) ā 5 and ā 6 are a pair of interior angles on the same side of the transversal.
(iv) ā 7 and ā 8 are a pair of corresponding angles.
(v) ā 9 and ā 10 are a pair of alternate interior angles.
(vi) ā 11 and ā 12 are linear pair of angles.

Try These (Page 109)

Question 1.

Solution:
(i) x = 60Ā°
[āµ x and 60Ā° are alternate interior angles]

(ii) y = 55Ā°
[āµ y and 55Ā° are alternate interior angles]

(iii) No, ā 1 and ā 2 are not equal.
[āµ l1 and 2 are not parallel]

(iv) āµ 60Ā° + z = 180Ā° ā z = 180Ā° – 60Ā° = 120Ā°
[āµ Z and 60Ā° are interior angles on the same side of the transversal]
ā“ z = 120Ā°

(v) x = 120Ā°
[x and 120Ā° are corresponding angles]

(vi) a + 60Ā° = 180Ā°
ā a = 180Ā° – 60Ā° = 120Ā°
a = d = 120Ā° [alternate exterior angles]
b + d = 180Ā° [linear pair]
ā b + 120Ā° = 180Ā°
ā 6 = 180Ā° – 120Ā° = 60Ā°
ā c = b = 60Ā°. [vertically opp. angles.]

Try These (Page 110)

Question 1.

Solution:
(i) If a transversal intersects two given lines such that alternate angles are equal, then the given lines are parallel.
āµ 50Ā° = 50Ā°
āµ Alternate angles are equal. Thus, l || m

(ii) l || m as pair of interior angles on the same side of the transversal are supplementary. Here, x = 130Ā° [vertically opposite]
and 50Ā° = 130Ā° = 180Ā° [Supplementary angles]

(iii) āµĀ  l and m are parallel and t is a transversal,
ā“ The sum of interior angles on the same side of the transversal is 180Ā°.
or x + 70Ā° = 180Ā°
or x = 180Ā° – 70Ā°
or x = 110Ā°