# GSEB Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.4

Gujarat BoardĀ GSEB Textbook Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.4 Textbook Questions and Answers.

## Gujarat Board Textbook Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.4

Question 1.
Find:
(i) 12 Ć· $$\frac { 3 }{ 4 }$$
(ii) 14Ć· $$\frac { 5 }{ 6 }$$
(iii) 8 Ć· $$\frac { 7 }{ 3 }$$
(iv) 4 Ć· $$\frac { 8 }{ 3 }$$
(v) 3 Ć· 2$$\frac { 1 }{ 3 }$$
(vi) 5 Ć· 3$$\frac { 4 }{ 7 }$$
Solution:

Question 2.
Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers.
(i) $$\frac { 3 }{ 7 }$$
(ii) $$\frac { 5 }{ 8 }$$
(iii) $$\frac { 9 }{ 7 }$$
(iv) $$\frac { 6 }{ 5 }$$
(v) $$\frac { 12 }{ 7 }$$
(vi) $$\frac { 1 }{ 8 }$$
(vii) $$\frac { 1 }{ 11 }$$
Solution:
(i) The recipocal of $$\frac { 3 }{ 7 }$$ is $$\frac { 7 }{ 3 }$$
(improper fraction)

(ii) The reciprocal of $$\frac { 5 }{ 8 }$$ is $$\frac { 8 }{ 5 }$$;
(improper fraction)

(iii) The reciprocal of $$\frac { 9 }{ 7 }$$ is $$\frac { 7 }{ 9 }$$;
(proper fraction)

(iv) The reciprocal of $$\frac { 6 }{ 5 }$$ is $$\frac { 5 }{ 6 }$$
(proper fraction)

(v) The reciprocal of $$\frac { 12 }{ 7 }$$ is $$\frac { 7 }{ 12 }$$
(proper fraction)

(vi) The reciprocal of $$\frac { 1 }{ 8 }$$ is 8;
(whole number)

(vii) The reciprocal of $$\frac { 1 }{ 11 }$$ is 11;
(whole number)

Question 3.
Find:
(i) $$\frac { 7 }{ 3 }$$ Ć· 2
(ii) $$\frac { 4 }{ 9 }$$ Ć· 5
(iii) $$\frac { 6 }{ 13 }$$ Ć· 7
(iv) 4$$\frac { 1 }{ 3 }$$ Ć· 3
(v) 3$$\frac { 1 }{ 2 }$$ Ć· 4
(vi) 4$$\frac { 4 }{ 7 }$$ Ć· 7
Solution:
(i) $$\frac { 7 }{ 3 }$$ Ć· 2
= $$\frac { 7 }{ 3 }$$ x $$\frac { 1 }{ 2 }$$
= 1$$\frac { 1 }{ 6 }$$

(ii) $$\frac { 4 }{ 9 }$$ Ć· 5
= $$\frac { 4 }{ 9 }$$ x $$\frac { 1 }{ 5 }$$
= $$\frac { 4 }{ 45 }$$

(iii) $$\frac { 6 }{ 13 }$$ Ć· 7
= $$\frac { 6 }{ 13 }$$ x $$\frac { 1 }{ 7 }$$
= $$\frac { 6 }{ 91 }$$

(iv) 4$$\frac { 1 }{ 3 }$$ Ć· 3
= $$\frac { 13 }{ 3 }$$ x $$\frac { 1 }{ 3 }$$
= 1$$\frac { 4 }{ 9 }$$

(v) 3$$\frac { 1 }{ 2 }$$ Ć· 4
= $$\frac { 7 }{ 2 }$$ x $$\frac { 1 }{ 4 }$$
= $$\frac { 7 }{ 8 }$$

(vi) 4$$\frac { 4 }{ 7 }$$ Ć· 7
= $$\frac { 31 }{ 7 }$$ x $$\frac { 1 }{ 7 }$$
= $$\frac { 31 }{ 49 }$$

Question 4.
(i) $$\frac { 2 }{ 5 }$$ Ć· $$\frac { 1 }{ 2 }$$
(ii) $$\frac { 4 }{ 9 }$$ Ć· $$\frac { 2 }{ 3 }$$
(iii) $$\frac { 3 }{ 7 }$$ Ć· $$\frac { 8 }{ 7 }$$
(iv) 2$$\frac { 1 }{ 3 }$$ Ć· $$\frac { 3 }{ 5 }$$
(v) 3$$\frac { 1 }{ 2 }$$ Ć· $$\frac { 8 }{ 3 }$$
(vi) 2$$\frac { 2 }{ 5 }$$ Ć· 1$$\frac { 1 }{ 2 }$$
(vii) 3$$\frac { 1 }{ 5 }$$ Ć· 1$$\frac { 2 }{ 3 }$$
(viii) 2$$\frac { 1 }{ 5 }$$ Ć· 1$$\frac { 1 }{ 5 }$$
Solution: