GSEB Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.4

Gujarat Board GSEB Textbook Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.4 Textbook Questions and Answers.

Gujarat Board Textbook Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.4

Question 1.
Find:
(i) 12 ÷ $\frac { 3 }{ 4 }$
(ii) 14÷ $\frac { 5 }{ 6 }$
(iii) 8 ÷ $\frac { 7 }{ 3 }$
(iv) 4 ÷ $\frac { 8 }{ 3 }$
(v) 3 ÷ 2$\frac { 1 }{ 3 }$
(vi) 5 ÷ 3$\frac { 4 }{ 7 }$
Solution:

Question 2.
Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers.
(i) $\frac { 3 }{ 7 }$
(ii) $\frac { 5 }{ 8 }$
(iii) $\frac { 9 }{ 7 }$
(iv) $\frac { 6 }{ 5 }$
(v) $\frac { 12 }{ 7 }$
(vi) $\frac { 1 }{ 8 }$
(vii) $\frac { 1 }{ 11 }$
Solution:
(i) The recipocal of $\frac { 3 }{ 7 }$ is $\frac { 7 }{ 3 }$
(improper fraction)

(ii) The reciprocal of $\frac { 5 }{ 8 }$ is $\frac { 8 }{ 5 }$;
(improper fraction)

(iii) The reciprocal of $\frac { 9 }{ 7 }$ is $\frac { 7 }{ 9 }$;
(proper fraction)

(iv) The reciprocal of $\frac { 6 }{ 5 }$ is $\frac { 5 }{ 6 }$
(proper fraction)

(v) The reciprocal of $\frac { 12 }{ 7 }$ is $\frac { 7 }{ 12 }$
(proper fraction)

(vi) The reciprocal of $\frac { 1 }{ 8 }$ is 8;
(whole number)

(vii) The reciprocal of $\frac { 1 }{ 11 }$ is 11;
(whole number)

Question 3.
Find:
(i) $\frac { 7 }{ 3 }$ ÷ 2
(ii) $\frac { 4 }{ 9 }$ ÷ 5
(iii) $\frac { 6 }{ 13 }$ ÷ 7
(iv) 4$\frac { 1 }{ 3 }$ ÷ 3
(v) 3$\frac { 1 }{ 2 }$ ÷ 4
(vi) 4$\frac { 4 }{ 7 }$ ÷ 7
Solution:
(i) $\frac { 7 }{ 3 }$ ÷ 2
= $\frac { 7 }{ 3 }$ x $\frac { 1 }{ 2 }$
= 1$\frac { 1 }{ 6 }$

(ii) $\frac { 4 }{ 9 }$ ÷ 5
= $\frac { 4 }{ 9 }$ x $\frac { 1 }{ 5 }$
= $\frac { 4 }{ 45 }$

(iii) $\frac { 6 }{ 13 }$ ÷ 7
= $\frac { 6 }{ 13 }$ x $\frac { 1 }{ 7 }$
= $\frac { 6 }{ 91 }$

(iv) 4$\frac { 1 }{ 3 }$ ÷ 3
= $\frac { 13 }{ 3 }$ x $\frac { 1 }{ 3 }$
= 1$\frac { 4 }{ 9 }$

(v) 3$\frac { 1 }{ 2 }$ ÷ 4
= $\frac { 7 }{ 2 }$ x $\frac { 1 }{ 4 }$
= $\frac { 7 }{ 8 }$

(vi) 4$\frac { 4 }{ 7 }$ ÷ 7
= $\frac { 31 }{ 7 }$ x $\frac { 1 }{ 7 }$
= $\frac { 31 }{ 49 }$

Question 4.
(i) $\frac { 2 }{ 5 }$ ÷ $\frac { 1 }{ 2 }$
(ii) $\frac { 4 }{ 9 }$ ÷ $\frac { 2 }{ 3 }$
(iii) $\frac { 3 }{ 7 }$ ÷ $\frac { 8 }{ 7 }$
(iv) 2$\frac { 1 }{ 3 }$ ÷ $\frac { 3 }{ 5 }$
(v) 3$\frac { 1 }{ 2 }$ ÷ $\frac { 8 }{ 3 }$
(vi) 2$\frac { 2 }{ 5 }$ ÷ 1$\frac { 1 }{ 2 }$
(vii) 3$\frac { 1 }{ 5 }$ ÷ 1$\frac { 2 }{ 3 }$
(viii) 2$\frac { 1 }{ 5 }$ ÷ 1$\frac { 1 }{ 5 }$
Solution: