Gujarat BoardĀ GSEB Textbook Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.2 Textbook Questions and Answers.

## Gujarat Board Textbook Solutions Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.2

Question 1.

Which of the drawings (a) to (d) show:

(i) 2 x \(\frac { 1 }{ 5 }\)

(ii) 2 x \(\frac { 1 }{ 2 }\)

(iii) 3 x \(\frac { 2 }{ 3 }\)

(iv) 3 x \(\frac { 1 }{ 4 }\)

Solution:

(i) 2 x \(\frac { 1 }{ 5 }\)

= \(\frac { 1 }{ 5 }\) + \(\frac { 1 }{ 5 }\), which is represented by the drawing (d).

Thus (i) ā (d).

(ii) 2 x \(\frac { 1 }{ 2 }\)

= \(\frac { 1 }{ 2 }\) + \(\frac { 1 }{ 2 }\), which is represented by the drawing (d).

Thus (ii) ā (d).

(iii) 3 x \(\frac { 2 }{ 3 }\)

\(\frac { 2 }{ 3 }\) + \(\frac { 2 }{ 3 }\) + \(\frac { 2 }{ 3 }\), which is represented by the drawing (a).

Thus, (iii) ā (a).

(iv) 3 x \(\frac { 1 }{ 4 }\)

\(\frac { 1 }{ 4 }\) + \(\frac { 1 }{ 4 }\) + \(\frac { 1 }{ 4 }\), which is represented by the drawing (c).

Thus, (iv) ā (c).

Question 2.

Some pictures (a) to (c) are given below. Tell which of them show:

(i) 3 x \(\frac { 1 }{ 5 }\)

(ii) 2 x \(\frac { 1 }{ 3 }\) = \(\frac { 2 }{ 3 }\)

(iii) 2 x \(\frac { 1 }{ 3 }\) = 2 x \(\frac { 1 }{ 4 }\)

Solution:

(i) āµ 3 x = \(\frac { 1 }{ 5 }\)

\(\frac { 1 }{ 5 }\) + \(\frac { 1 }{ 5 }\) + \(\frac { 1 }{ 5 }\) = \(\frac { 3 }{ 5 }\), which is shown by the drawing (c).

ā“ (i) ā (C)

(ii) āµ 2 x \(\frac { 1 }{ 3 }\) = \(\frac { 1 }{ 3 }\) + \(\frac { 1 }{ 3 }\) = \(\frac { 2 }{ 3 }\), which is shown by the drawing (a).

ā“ (ii) ā (C)

(iii) āµ 3 x \(\frac { 3 }{ 4 }\) = \(\frac { 3 }{ 4 }\) + \(\frac { 3 }{ 4 }\) + \(\frac { 3 }{ 4 }\), which is shown by the drawing (a).

ā“ (iii) ā (C)

Question 3.

Multiply and reduce to lowest form and convert into a mixed fraction:

(i) 7 x \(\frac { 3 }{ 5 }\)

(ii) 4 x \(\frac { 1 }{ 3 }\)

(iii) 2 x \(\frac { 6 }{ 7 }\)

(iv) 5 x \(\frac { 2 }{ 9 }\)

(v) \(\frac { 2 }{ 3 }\) x 4

(vi) \(\frac { 5 }{ 2 }\) x 6

(vii) 11 x \(\frac { 4 }{ 7 }\)

(viii) 20 x \(\frac { 4 }{ 5 }\)

(ix) 13 x \(\frac { 1 }{ 3 }\)

(x) 15 x \(\frac { 3 }{ 5 }\)

Solution:

Question 4.

Shade:

(i) \(\frac { 1 }{ 2 }\) of the circles in box (a)

(ii) \(\frac { 2 }{ 3 }\) of the triangles in box (b)

(ii) \(\frac { 3 }{ 5 }\) of the squares in box (c)

Solution:

(i) \(\frac { 1 }{ 2 }\) of the circles:

āµ \(\frac { 1 }{ 2 }\) of 12 = \(\frac { 1 }{ 2 }\) x 12 = 6

So, we shade 6 circles.

(ii) \(\frac { 2 }{ 3 }\) of the triangles:

āµ \(\frac { 2 }{ 3 }\) of 9 = \(\frac { 2 Ć 9 }{ 3 }\) = 6

ā“ We shade 6 triangles

(ii) \(\frac { 3 }{ 5 }\) of the squares:

āµ \(\frac { 3 }{ 5 }\) or 15 = \(\frac { 3 Ć 15 }{ 5 }\) = 9

ā“ We shade 9 squares.

Question 5.

Find:

(a) \(\frac { 1 }{ 2 }\) of (i) 24 (ii) 46

(b) \(\frac { 2 }{ 3 }\) of (i) 18 (ii) 27

(c) \(\frac { 3 }{ 4 }\) of (i) 16 (ii) 36

(d) \(\frac { 4 }{ 5 }\) of (i) 20 (ii) 35

Solution:

Question 6.

Multiply and express as a mixed fraction:

(a) 3 x 5\(\frac { 1 }{ 5 }\)

(b) 5 x 6\(\frac { 3 }{ 4 }\)

(c) 7 x 2\(\frac { 1 }{ 4 }\)

(d) 4 x 6\(\frac { 1 }{ 3 }\)

(e) 3\(\frac { 1 }{ 4 }\) x 6

(f) 3\(\frac { 2 }{ 5 }\) x 8

Solution:

Question 7.

Find:

(a) \(\frac { 1 }{ 2 }\) of (i) 2\(\frac { 3 }{ 4 }\) (ii) 4\(\frac { 2 }{ 9 }\)

(b) \(\frac { 5 }{ 8 }\) of (i) 3\(\frac { 5 }{ 6 }\) (ii) 9\(\frac { 2 }{ 3 }\)

Solution:

(a) (i) \(\frac { 1 }{ 2 }\) of 2\(\frac { 3 }{ 4 }\)

= \(\frac { 1 }{ 2 }\) of \(\frac { 11 }{ 4 }\)

= \(\frac { 1Ć11 }{ 2Ć4 }\)

= \(\frac { 11 }{ 8 }\)

= 1\(\frac { 3 }{ 8 }\)

(ii) \(\frac { 1 }{ 2 }\) of 4\(\frac { 2 }{ 9 }\)

= \(\frac { 1 }{ 2 }\) of \(\frac { 38 }{ 9 }\)

= \(\frac { 1Ć38 }{ 2Ć9 }\)

= \(\frac { 19 }{ 9 }\)

= 2\(\frac { 1 }{ 9 }\)

(b) (i) \(\frac { 5 }{ 8 }\) of 3\(\frac { 5 }{ 6 }\)

= \(\frac { 5 }{ 8 }\) of \(\frac { 23 }{ 6 }\)

= \(\frac { 5Ć23 }{ 8Ć6 }\)

= \(\frac { 115 }{ 48 }\)

= 2\(\frac { 19 }{ 48 }\)

(ii) \(\frac { 5 }{ 8 }\) of 9\(\frac { 2 }{ 3 }\)

= \(\frac { 5 }{ 8 }\) of \(\frac { 29 }{ 3 }\)

= \(\frac { 5Ć29 }{ 8Ć3 }\)

= \(\frac { 145 }{ 24 }\)

= 6\(\frac { 1 }{ 24 }\)

Question 8.

Vidya and Pratap went for a picnic. Their mother gave them a water bottle that contained 5 litres of water. Vidya consumed \(\frac { 2 }{ 5 }\) of the water.

Pratap consumed the remaining water.

(i) How much water did Vidya drink7

(ii) What fraction of the total quantity of water did Pratap drink?

Solution:

Total quantity of water = 5 litres

(i) Amount of water consumed by Vidya = \(\frac { 2 }{ 5 }\) of 5 litres = \(\frac { 2 }{ 5 }\) x 5 litres = 2 litres

(ii) Remaining water = water consumed by Pratap

i.e. Amount of water consumed by Pratap = 5 litres – 2 litres = 3 litres

Fraction of water consumed by Pratap = \(\frac { 3 }{ 5 }\)