# GSEB Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4

Gujarat BoardĀ GSEB Textbook Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4 Textbook Questions and Answers.

## Gujarat Board Textbook Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4

Question 1.
Express as rupees using decimals.
(a) 5 paise
(b) 75 paise
(c) 20 paise
(d) 50 rupees 90 paise
(e) 725 paise
Solution:
(a) 5 paise
āµ 1 paisa = ā¹ $$\frac { 1 }{ 100 }$$
ā“ 5 paise = ā¹ 5 Ć $$\frac { 1 }{ 100 }$$ = ā¹ $$\frac { 5 }{ 100 }$$ = ā¹ 0.05

(b) 75 paise
āµ 1 paisa = ā¹ $$\frac { 1 }{ 100 }$$
75 paise = ā¹ 75 Ć $$\frac { 1 }{ 100 }$$ = ā¹ $$\frac { 75 }{ 100 }$$ = ā¹ 0.75

(c) 20 paise
āµ 1 paisa = ā¹ $$\frac { 1 }{ 100 }$$
ā“ 20 paise = ā¹ 20 Ć $$\frac { 1 }{ 100 }$$ = ā¹ $$\frac { 20 }{ 100 }$$ = ā¹ 0.20

(d) 50 rupees 90 paise
āµ 1 paisa = ā¹ $$\frac { 1 }{ 100 }$$
ā“ 90 paise = ā¹ 90 Ć $$\frac { 1 }{ 100 }$$ = ā¹ 0.90
Now, 50 rupees + 90 paise
= ā¹ 50 + ā¹ 0.90 = ā¹ (50 + 0.90) = ā¹ 50.90

(e) 725 paise
āµ 1 paisa = ā¹ $$\frac { 1 }{ 100 }$$
ā“ 725 paise = ā¹ 725 Ć $$\frac { 1 }{ 100 }$$ = ā¹ $$\frac { 725 }{ 100 }$$
= ā¹ [7 + 0.25] = ā¹ 7.25

Question 2.
Express as km using decimals.
(a) 15 cm
(b) 6 cm
(c) 2 m 45 cm
(d) 9 m 7 cm
(e) 419 cm
Solution:
(a) 15 cm
āµ 100 cm = 1 m
ā“ 1 cm = $$\frac { 1 }{ 100 }$$ m
So 15 cm = 15 Ć $$\frac { 1 }{ 100 }$$m = $$\frac { 15 }{ 100 }$$m = 0.15 m

(b) 6 cm
āµ 1 cm = $$\frac { 1 }{ 100 }$$ m
ā“ 6 cm = $$\frac { 1 }{ 100 }$$ m = $$\frac { 6 }{ 100 }$$m = 0.06 m

(c) 2 m 45 cm
āµ 1 cm = $$\frac { 1 }{ 100 }$$ m
ā“ 2 m 45 cm = 2 m + 45 cm
2 m 45 cm = 2 m + 45 Ć $$\frac { 1 }{ 100 }$$ m
= 2 m + 0.45 m
= (2 + 0.45) m = 2.45 m

(d) 9 m 7 cm
āµ 1 cm = $$\frac { 1 }{ 100 }$$ m
ā“ 9 m 7 cm = 9 m + 7 cm
9 m + 7 cm = 9 m + 7 Ć $$\frac { 1 }{ 100 }$$ m
= 9 m + 0.07 m
9 m 7 cm = (9 + 0.07)m = 9.07 m

(e) 419 cm
āµ 1 cm = $$\frac { 1 }{ 100 }$$ m
ā“ 419 cm = 419 Ć $$\frac { 1 }{ 100 }$$ m = $$\frac { 419 }{ 100 }$$ m
= $$\left(\frac{400}{100}+\frac{19}{100}\right)$$ m = $$\left(4+\frac{19}{100}\right)$$ m
= (4 + 0.19) m = 4.19 m

Question 3.
(a) 5 mm
(b) 60 mm
(c) 164 mm
(d) 9 cm 8 mm
(e) 93 mm
Solution:
(a) 5 mm
āµ 1 mm = $$\frac { 1 }{ 10 }$$ cm
ā“ 5 mm = 5 Ć $$\frac { 1 }{ 10 }$$ cm = $$\frac { 5 }{ 10 }$$ cm = 0.5 cm

(b) 60 mm
āµ 1 mm = $$\frac { 1 }{ 10 }$$ cm
ā“ 60 mm = 60 Ć $$\frac { 1 }{ 10 }$$ cm = $$\frac { 60 }{ 10 }$$ cm = 6.0 cm

(c) 164 mm
āµ 1 mm = $$\frac { 1 }{ 10 }$$ cm
ā“ 164 mm = 164 Ć $$\frac { 1 }{ 10 }$$ cm = $$\frac { 164 }{ 10 }$$ cm
= $$\left(\frac{100+60+4}{10}\right)$$ cm = $$\left(\frac{100}{10}+\frac{60}{10}+\frac{4}{10}\right)$$ cm
= $$\left(10+6+\frac{4}{10}\right)$$ cm = 16.4 cm

(d) 9 cm 8 mm
āµ 1 mm = $$\frac { 1 }{ 10 }$$ cm and 9 cm 8 mm = 9 cm 8 mm
ā“ 9 cm 8 mm = 9 cm + 8 Ć $$\frac { 1 }{ 10 }$$ cm
= 9 cm + 0.8 cm
= (9 + 0.8) cm = 9.8 cm

(e) 93 mm
āµ 1 mm = $$\frac { 1 }{ 10 }$$ cm
ā“ 93 mm = 93 Ć $$\frac { 1 }{ 10 }$$ cm
= $$\frac { 93 }{ 10 }$$ cm = $$\left(\frac{90}{10}+\frac{3}{10}\right)$$ cm
= (9 + 0.3) cm = 9.3 cm

Question 4.
Express as km using decimals.
(a) 8 m
(b) 88 m
(c) 8888 m
(d) 70 km 5 m
Solution:
(a) 8 m
āµ 1000 m = 1 m
ā“ 1 m = $$\frac { 1 }{ 1000 }$$ km
Now, 8 m = 8 Ć $$\frac { 1 }{ 1000 }$$ km
= $$\frac { 8 }{ 1000 }$$ km = 0.008 km

(b) 88 m
āµ 1000 m = 1 m
ā“ 1 m = $$\frac { 1 }{ 1000 }$$ km
Now, 8 m = 88 Ć $$\frac { 1 }{ 1000 }$$ km
= $$\frac { 88 }{ 1000 }$$ km = 0.088 km

(c) 8888 m
āµ 1 m = $$\frac { 1 }{ 1000 }$$ km
ā“ 8888 m = 8888 Ć $$\frac { 1 }{ 1000 }$$ km = $$\frac { 8888 }{ 1000 }$$ km
= $$\left[\frac{8000+888}{1000}\right]$$ km = $$\left[\frac{8000}{1000}+\frac{888}{1000}\right]$$ km
= [8 + 0.888] km = 8.888 km

(d) 70 km 5 m
āµ 1 m = $$\frac { 1 }{ 1000 }$$ km and 70 km 5 m = 70 km + 5 m
ā“ 70 km 5 m = 70 km + 5 Ć $$\frac { 1 }{ 1000 }$$ km
= $$\left[70+\frac{5}{1000}\right]$$ km
= [70 + 0.005] km = 70.005 km

Question 5.
Express as kg using decimals.
(a) 2 g
(b) 100 g
(c) 3750 g
(d) 5 kg 8 g
(e) 26 kg 50 g
Solution:
(a) 2 g
āµ 1000 g = 1 kg
ā“ 1 g = $$\frac { 1 }{ 1000 }$$ kg
Now 2 g = 2 Ć $$\frac { 1 }{ 1000 }$$ kg
= $$\frac { 2 }{ 1000 }$$ kg = 0.002 kg

(b) 100 g
āµ 1 g = $$\frac { 1 }{ 1000 }$$ kg
ā“ 100 g = $$\frac { 1 }{ 1000 }$$ kg
= $$\frac { 1 }{ 1000 }$$ kg Ć 100 kg = 0.1 kg

(c) 3750 g
āµ 1 g = $$\frac { 1 }{ 1000 }$$ kg
ā“ 3750 g = 3750 Ć $$\frac { 1 }{ 1000 }$$ kg
= $$\frac { 3750 }{ 1000 }$$ kg
= $$\left(\frac{3000+750}{1000}\right)$$ kg = $$\left(\frac{3000}{1000}+\frac{750}{1000}\right)$$ kg
= (3 + 0.750) kg = 3.750 kg

(d) 5 kg 8 g
āµ 1 g = $$\frac { 1 }{ 1000 }$$ kg and 5 kg 8 g = 5 kg + 8 g
ā“ 5 kg 8 g = 5 kg + 8 Ć $$\frac { 1 }{ 1000 }$$ kg
= $$\left(5+\frac{8}{1000}\right)$$ kg
= (5 + 0.008) kg = 5.008 kg

(e) 26 kg 50 g
āµ 1 g = $$\frac { 1 }{ 1000 }$$ kg and 26 kg 50 g = 26 kg + 50 g
ā“ 26 kg 50 g = 26 kg + 50 Ć $$\frac { 1 }{ 1000 }$$ kg
= 26 kg + $$\frac { 50 }{ 1000 }$$ kg = $$\left(26+\frac{50}{1000}\right)$$ kg
= (26 + 0.050) kg = 26.050 kg