GSEB Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4

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Gujarat BoardĀ GSEB Textbook Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4 Textbook Questions and Answers.

Gujarat Board Textbook Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4

Question 1.
Express as rupees using decimals.
(a) 5 paise
(b) 75 paise
(c) 20 paise
(d) 50 rupees 90 paise
(e) 725 paise
Solution:
(a) 5 paise
āˆµ 1 paisa = ā‚¹ \(\frac { 1 }{ 100 }\)
āˆ“ 5 paise = ā‚¹ 5 Ɨ \(\frac { 1 }{ 100 }\) = ā‚¹ \(\frac { 5 }{ 100 }\) = ā‚¹ 0.05

(b) 75 paise
āˆµ 1 paisa = ā‚¹ \(\frac { 1 }{ 100 }\)
75 paise = ā‚¹ 75 Ɨ \(\frac { 1 }{ 100 }\) = ā‚¹ \(\frac { 75 }{ 100 }\) = ā‚¹ 0.75

(c) 20 paise
āˆµ 1 paisa = ā‚¹ \(\frac { 1 }{ 100 }\)
āˆ“ 20 paise = ā‚¹ 20 Ɨ \(\frac { 1 }{ 100 }\) = ā‚¹ \(\frac { 20 }{ 100 }\) = ā‚¹ 0.20

(d) 50 rupees 90 paise
āˆµ 1 paisa = ā‚¹ \(\frac { 1 }{ 100 }\)
āˆ“ 90 paise = ā‚¹ 90 Ɨ \(\frac { 1 }{ 100 }\) = ā‚¹ 0.90
Now, 50 rupees + 90 paise
= ā‚¹ 50 + ā‚¹ 0.90 = ā‚¹ (50 + 0.90) = ā‚¹ 50.90

(e) 725 paise
āˆµ 1 paisa = ā‚¹ \(\frac { 1 }{ 100 }\)
āˆ“ 725 paise = ā‚¹ 725 Ɨ \(\frac { 1 }{ 100 }\) = ā‚¹ \(\frac { 725 }{ 100 }\)
= ā‚¹ [7 + 0.25] = ā‚¹ 7.25

GSEB Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4

Question 2.
Express as km using decimals.
(a) 15 cm
(b) 6 cm
(c) 2 m 45 cm
(d) 9 m 7 cm
(e) 419 cm
Solution:
(a) 15 cm
āˆµ 100 cm = 1 m
āˆ“ 1 cm = \(\frac { 1 }{ 100 }\) m
So 15 cm = 15 Ɨ \(\frac { 1 }{ 100 }\)m = \(\frac { 15 }{ 100 }\)m = 0.15 m

(b) 6 cm
āˆµ 1 cm = \(\frac { 1 }{ 100 }\) m
āˆ“ 6 cm = \(\frac { 1 }{ 100 }\) m = \(\frac { 6 }{ 100 }\)m = 0.06 m

(c) 2 m 45 cm
āˆµ 1 cm = \(\frac { 1 }{ 100 }\) m
āˆ“ 2 m 45 cm = 2 m + 45 cm
2 m 45 cm = 2 m + 45 Ɨ \(\frac { 1 }{ 100 }\) m
= 2 m + 0.45 m
= (2 + 0.45) m = 2.45 m

(d) 9 m 7 cm
āˆµ 1 cm = \(\frac { 1 }{ 100 }\) m
āˆ“ 9 m 7 cm = 9 m + 7 cm
9 m + 7 cm = 9 m + 7 Ɨ \(\frac { 1 }{ 100 }\) m
= 9 m + 0.07 m
9 m 7 cm = (9 + 0.07)m = 9.07 m

(e) 419 cm
āˆµ 1 cm = \(\frac { 1 }{ 100 }\) m
āˆ“ 419 cm = 419 Ɨ \(\frac { 1 }{ 100 }\) m = \(\frac { 419 }{ 100 }\) m
= \(\left(\frac{400}{100}+\frac{19}{100}\right)\) m = \(\left(4+\frac{19}{100}\right)\) m
= (4 + 0.19) m = 4.19 m

GSEB Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4

Question 3.
(a) 5 mm
(b) 60 mm
(c) 164 mm
(d) 9 cm 8 mm
(e) 93 mm
Solution:
(a) 5 mm
āˆµ 1 mm = \(\frac { 1 }{ 10 }\) cm
āˆ“ 5 mm = 5 Ɨ \(\frac { 1 }{ 10 }\) cm = \(\frac { 5 }{ 10 }\) cm = 0.5 cm

(b) 60 mm
āˆµ 1 mm = \(\frac { 1 }{ 10 }\) cm
āˆ“ 60 mm = 60 Ɨ \(\frac { 1 }{ 10 }\) cm = \(\frac { 60 }{ 10 }\) cm = 6.0 cm

(c) 164 mm
āˆµ 1 mm = \(\frac { 1 }{ 10 }\) cm
āˆ“ 164 mm = 164 Ɨ \(\frac { 1 }{ 10 }\) cm = \(\frac { 164 }{ 10 }\) cm
= \(\left(\frac{100+60+4}{10}\right)\) cm = \(\left(\frac{100}{10}+\frac{60}{10}+\frac{4}{10}\right)\) cm
= \(\left(10+6+\frac{4}{10}\right)\) cm = 16.4 cm

(d) 9 cm 8 mm
āˆµ 1 mm = \(\frac { 1 }{ 10 }\) cm and 9 cm 8 mm = 9 cm 8 mm
āˆ“ 9 cm 8 mm = 9 cm + 8 Ɨ \(\frac { 1 }{ 10 }\) cm
= 9 cm + 0.8 cm
= (9 + 0.8) cm = 9.8 cm

(e) 93 mm
āˆµ 1 mm = \(\frac { 1 }{ 10 }\) cm
āˆ“ 93 mm = 93 Ɨ \(\frac { 1 }{ 10 }\) cm
= \(\frac { 93 }{ 10 }\) cm = \(\left(\frac{90}{10}+\frac{3}{10}\right)\) cm
= (9 + 0.3) cm = 9.3 cm

GSEB Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4

Question 4.
Express as km using decimals.
(a) 8 m
(b) 88 m
(c) 8888 m
(d) 70 km 5 m
Solution:
(a) 8 m
āˆµ 1000 m = 1 m
āˆ“ 1 m = \(\frac { 1 }{ 1000 }\) km
Now, 8 m = 8 Ɨ \(\frac { 1 }{ 1000 }\) km
= \(\frac { 8 }{ 1000 }\) km = 0.008 km

(b) 88 m
āˆµ 1000 m = 1 m
āˆ“ 1 m = \(\frac { 1 }{ 1000 }\) km
Now, 8 m = 88 Ɨ \(\frac { 1 }{ 1000 }\) km
= \(\frac { 88 }{ 1000 }\) km = 0.088 km

(c) 8888 m
āˆµ 1 m = \(\frac { 1 }{ 1000 }\) km
āˆ“ 8888 m = 8888 Ɨ \(\frac { 1 }{ 1000 }\) km = \(\frac { 8888 }{ 1000 }\) km
= \(\left[\frac{8000+888}{1000}\right]\) km = \(\left[\frac{8000}{1000}+\frac{888}{1000}\right]\) km
= [8 + 0.888] km = 8.888 km

(d) 70 km 5 m
āˆµ 1 m = \(\frac { 1 }{ 1000 }\) km and 70 km 5 m = 70 km + 5 m
āˆ“ 70 km 5 m = 70 km + 5 Ɨ \(\frac { 1 }{ 1000 }\) km
= \(\left[70+\frac{5}{1000}\right]\) km
= [70 + 0.005] km = 70.005 km

GSEB Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4

Question 5.
Express as kg using decimals.
(a) 2 g
(b) 100 g
(c) 3750 g
(d) 5 kg 8 g
(e) 26 kg 50 g
Solution:
(a) 2 g
āˆµ 1000 g = 1 kg
āˆ“ 1 g = \(\frac { 1 }{ 1000 }\) kg
Now 2 g = 2 Ɨ \(\frac { 1 }{ 1000 }\) kg
= \(\frac { 2 }{ 1000 }\) kg = 0.002 kg

(b) 100 g
āˆµ 1 g = \(\frac { 1 }{ 1000 }\) kg
āˆ“ 100 g = \(\frac { 1 }{ 1000 }\) kg
= \(\frac { 1 }{ 1000 }\) kg Ɨ 100 kg = 0.1 kg

(c) 3750 g
āˆµ 1 g = \(\frac { 1 }{ 1000 }\) kg
āˆ“ 3750 g = 3750 Ɨ \(\frac { 1 }{ 1000 }\) kg
= \(\frac { 3750 }{ 1000 }\) kg
= \(\left(\frac{3000+750}{1000}\right)\) kg = \(\left(\frac{3000}{1000}+\frac{750}{1000}\right)\) kg
= (3 + 0.750) kg = 3.750 kg

(d) 5 kg 8 g
āˆµ 1 g = \(\frac { 1 }{ 1000 }\) kg and 5 kg 8 g = 5 kg + 8 g
āˆ“ 5 kg 8 g = 5 kg + 8 Ɨ \(\frac { 1 }{ 1000 }\) kg
= \(\left(5+\frac{8}{1000}\right)\) kg
= (5 + 0.008) kg = 5.008 kg

(e) 26 kg 50 g
āˆµ 1 g = \(\frac { 1 }{ 1000 }\) kg and 26 kg 50 g = 26 kg + 50 g
āˆ“ 26 kg 50 g = 26 kg + 50 Ɨ \(\frac { 1 }{ 1000 }\) kg
= 26 kg + \(\frac { 50 }{ 1000 }\) kg = \(\left(26+\frac{50}{1000}\right)\) kg
= (26 + 0.050) kg = 26.050 kg

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