# GSEB Solutions Class 6 Maths Chapter 2 Whole Numbers InText Questions

Gujarat Board GSEB Textbook Solutions Class 6 Maths Chapter 2 Whole Numbers InText Questions and Answers.

## Gujarat Board Textbook Solutions Class 6 Maths Chapter 2 Whole Numbers InText Questions

Try These (Page 28)

Question 1.
Write the predecessor and successor of 19; 1997; 12000; 49; 100000.
Solution: Question 2.
Is there any natural number that has no predecessor?
Solution.
Yes, the smallest natural number I has no predecessor.

Question 3.
Is there any natural number which has no successor? Is there a last natural number?
Solution:
(i) No, there is no natural number which has no successor.
(ii) No, there is no last natural number. Try These (Page 29)

Question 1.
Are all natural numbers also whole numbers?
Solution:
Yes, all natural numbers are whole numbers.

Question 2.
Are all whole numbers also natural numbers?
Solution:
No, all whole numbers are not natural numbers. Because 0 is a whole number but it is not a natural number.

Question 3.
Which is the greatest whole number?
Solution:
Since, every whole number has a successor.
There is no greatest whole number. Try These (Page 30)

Question 1.
Find 4 + 5; 2 + 6; 3 + 5 and 1 + 6 using the number line.
Solution:
(i) 4 + 5 Let us start from 4. Since, we have to add 5 to this number, we make 5 jumps to the right.
Each jump being equal to 1 unit. After five jumps we reach at 9 (as shown above).
4 + 5 = 9

(ii) 2 + 6 Let us start from 2. Since, we have to add 6 to this number, we make 6 equal jumps, each
jump being equal to 1 unit, to the right and reach to 8.
2 + 6 = 8

(iii) 3 + 5 We have to add 5 to 3.
We start from 3. We make 5 equal jumps. Each jump being equal to 1 unit (as shown
in the figure) to the right and reach to 8.
3 + 5 = 8

(iv) 1 + 6 As we have to add 6 to 1, therefore, we start from 1 and make 6 equal jumps to the right.
Each jump being equal to 1 unit.
We reach to 7.
1 + 6 = 7 Try These (Page 30)

Question 1.
Find 8 – 3; 6 – 2; 9 – 6 using the number line.
Solution:
(i) 8 – 3 To subtract 3 from 8, start from 8 and make 3 equal jumps towards left. Each jump being
equal to 1 unit.
So, we reach at 5, 8 – 3 = 5.

(ii) 6 – 2 To subtract 2 from 6, we start from 6. Make 2 equal jumps towards left. Each jump being
equal to 1 unit.
So, we reach at 4, 6 – 2 = 4

(iii) 9 – 6 To subtract 6 from 9, we start from 9 and make 6 equal jumps towards left. Each jump
being equal to 1 unit.
So, we reach at 3, 9 – 6 = 3 Try These (Page 31)

Question 1.
Find 2 x 6, 3 x 3; 4 x 2 using the number line.
Solution:
(i) 2 x 6 Starting from 0, move 2 units at a time to the right. Make 6 such moves.
So. we reach at 12
2 x 6 = 12

(ii) 3 x 3 Starting from 0, move 3 units at a time to the right. Make 3 such moves.
So, we reach at 9,
3 x 3 = 9

(iii) 4 x 2 Starting from 0, move 4 units at a time to the right. Make 2 such moves.
So, we reach at 8,
4 x 2 = 8 Try These (Page 37)

Question 1.
Find: 7 + 18 + 13; 16 + 12 + 4
Solution:
(i) 7 + 18 + 13 = (7 + 13) + 18
= 20 + 18 = 38

(ii) 16 + 12 + 4 = (16 + 4) + 12
= 20 + 12 = 32

Try These (Page 37)

Question 1.
Find: 25 x 8358 x 4; 625 x 3759 x 8
(i) 25 x 8358 x 4 = (25 x 4) x 8358
(Using associativity of whole numbers)
= (100) x 8358 = 835800

(ii) 625 x 3759 x 8= (625 x 8) x 3759
(Using associativity of whole numbers)
= 5000 x 3759
= 5 x 1000 x 3759
= (3759 x 5) x 1000
= 18795 x 1001) = 18795000
625 x 3759 x 8 = 18795000 Try These (Page 39)

Question 1.
Find 15 x 68; 17 x 23; 69 x 78 + 22 x 69
using distributive property.
Solution:
(i) 15 x 68 = (10 + 5) x 68
= (10 x 68) + (5 x 68)
(By distributivity of multiplication over addition)
= 680 + 340 = 1020

(ii) 17 x 23 = 17 x (20 + 3)
= (17 x 20) + (17 x 3)
(By distributivity of multiplication Over addition)
= 340 + 51 = 391

(iii) 69 x 78 + 22 x 69 = 69[78 + 22]
= 69
= 6900
69 x 78 + 22 x 69 = 6900 Try These (Page 42)

Question 1.
Which numbers can be shown. only as a line?
Solution:
The numbers 2, 5, 7, 11, 13, 14, 17, 19, … can be shown only as a line.

Question 2.
Which can be shown as squares?
Solution.
The numbers 4, 9, 16, 25 … .can be shown as squares.

Question 3.
Which can be shown as rectangles?
Solution:
The numbers like 4, 6, 8, 9, 10, 12, … can be shown as rectangles.

Question 4.
Write down the first seven numbers that can be arranged as triangles, e.g. 3, 6, …
Solution:
We have Thus, the first seven triangular numbers are: 3, 6, 10, 15, 21, 28 and 36. Question 5.
Some numbers can be shown by two rectangles, for example, Give at least five other such examples.
Solution:
There can be many such examples. Some of them are as follows: 