Gujarat Board Statistics Class 12 GSEB Solutions Part 2 Chapter 5 Differentiation Ex 5.1 Textbook Exercise Questions and Answers.

## Gujarat Board Textbook Solutions Class 12 Statistics Part 2 Chapter 5 Differentiation Ex 5.1

Obtain the derivatives of the following functions with the help of definition:

Question 1.

f(x) = 2x + 3

Solution:

Here, f(x) = 2x + 3

âˆ´ f(x + h) = 2 (x + h) + 3 = 2x + 2h + 3

Hence, f(x) = 2x + 3 then fâ€™(x) = 2.

f(x) = x^{2}

Solution:

Here, f(x) = x^{2}

âˆ´ f(x + h) = (x + h)^{2} = x^{2} + 2xh + h^{2}

Hence, f(x) = x^{2} then f'(x) = 2x.

Question 3.

f(x) = x^{7}

Solution:

Here, f(x) = x^{7}

âˆ´ f(x + h) = (x + h)^{7}

Take, x + h = t, when h â†’ 0, t â†’ x and h = t – x

Hence, f(x) = x^{7} then f'(x) = 7x^{6}

Question 4.

f(x) = \(\frac{1}{x+1}\), x â‰ -1

Solution:

Here, f(x) = \(\frac{1}{x+1}\)

âˆ´ f(x + h) = f(x)

Hence, f(x) = \(\frac{1}{x+1}\) then f'(x) = \(-\frac{1}{(x+1)^{2}}\).

Question 5.

f(x) = \(\sqrt[3]{x}\)

solution:

Here, f(x) = \(\sqrt[3]{x}=x^{\frac{1}{3}}\)

âˆ´ f(x + h) = \((x+h)^{\frac{1}{3}}\)

Take, x + h = t, when h â†’ 0, t â†’ x and h = t – x

Hence, f(x) = \(\sqrt[3]{x}\) then f'(x) = \(\frac{1}{3 \cdot x^{\frac{2}{3}}}\).

Question 6.

f(x) = 24, x â‰ \(\frac{4}{3}\)

Solution:

Here, f(x) = \(\frac{2}{3 x-4}\)

âˆ´ f(x + h) = \(\frac{2}{3(x+h)-4}\)

Hence, f(x) = \(\frac{2}{3(x+h)-4}\) then fâ€™(x) = \(\frac{-6}{(3 x-4)^{2}}\).

Question 7.

f(x) = 10

Solution:

Here, f(x) = 10

âˆ´ f(x + h) = 10

Hence, f(x) = 10 then fâ€™(x) = 0