Gujarat Board GSEB Textbook Solutions Class 7 Maths Chapter 10 Practical Geometry Ex 10.2 Textbook Questions and Answers.

## Gujarat Board Textbook Solutions Class 7 Maths Chapter 10 Practical Geometry Ex 10.2

Question 1.

Construct ∆XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

Solution:

Steps of construction:

I. Draw a line segment YZ = 5 cm.

II. With centre Y and radius 4.5 cm, draw an arc.

III. With centre Z and radius 6 cm, draw another arc to cut the previous arc at X.

IV. Join YX and ZX.

Thus, ∆XYZ is the required triangle.

Question 2.

Construct an equilateral triangle of side 5.5 cm.

Solution:

Steps of construction:

I. Draw a line segment BC = 5.5 cm.

II. With B as centre and radius 5.5 cm, draw an arc.

III. With centre C and radius 5.5 cm, draw another arc to cut the previous arc at A.

IV. Join BA and CA.

Thus, ∆ABC is the required equilateral triangle.

Question 3.

Draw ∆PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?

Solution:

Steps of construction:

I. Draw a line segment QR = 3.5 cm.

II. With Q as centre and radius 4 cm, draw an arc.

III. With R as centre and radius 4 cm, draw another arc such that it cuts the previous arc at R

IV. Join QP and RP.

Thus, ∆PQR is the required triangle.

Since, PQ = PR = 4 cm

Therefore, PQR is an isosceles triangle.

Question 4.

Construct ∆ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.

Solution:

Steps of construction:

I. Draw a line segment BC = 6 cm.

II. With centre as B and radius 2.5 cm, draw an arc.

III. With centre C and radius 6.5 cm, draw another arc such that it cuts the previous arc at A.

IV. Join BA and CA.

Thus, ∆ABC is the required triangle. On measuring, we find that ∠B = 90°.