Gujarat Board GSEB Textbook Solutions Class 6 Maths Chapter 11 Algebra Ex 11.3 Textbook Questions and Answers.

## Gujarat Board Textbook Solutions Class 6 Maths Chapter 11 Algebra Ex 11.3

Question 1.

Makeup as many expressions with numbers {no variables) as you can from three numbers 5, 7, and 8. Every number should be used not more than once. Use only addition, subtraction, and multiplication.

Hint: Three possible expressions are 5 + (8 – 7), 5 – (8 – 7), (5 x 8) + 7; make the other expressions.

Solution:

Here, we have to use the given three numbers altogether. In an expression, every number is not to be used more than once.

Thus, we can have:

(i) 5 + (7 + 8)

(ii) 7 × 5 + 8

(iii) (8 – 5) × 7

(iv) (7 – 5) × 8

(v) (5 × 7) – 8

(vi) (8 × 7) + 5

(vii) 8 – 5 + 7

(viii) (8 – 7) + 5, etc.

Question 2.

Which out of the following are expressions with numbers only?

(a) y + 3

(b) (7 × 20) – 8z

(c) 5(21 -7) + 7 × 2

(d) 5

(e) 3x

(f) 5 – 5n

(g) (7 × 20) – (5 × 10) – 45 + p

Solution:

In expressions (c) and (d) no variable is involved.

∵ (c) and (d) are expressions with numbers only.

Question 3.

Identify the operations (addition, subtraction, division, multiplication) informing the following expressions and tell how the expressions have been formed.

(a) z + 1, z – l, y + 17, y – 17

(b) 17y, \(\frac{y}{17}\), 5z

(c) 2y + 17, 2y – 17

(d) 7m, – 7m + 3, – 7m – 3

Solution:

Question 4.

Give expressions for the following cases.

(a) 7 added to p

(b) 7 subtracted from p

(c) p multiplied by 7

(d) p divided by 7

(e) 7 subtracted from -m

(f) -p multiplied by 5

(g) -p divided by 5

(h) p multiplied by -5

Solution:

(a) P + 7

(b) p – 7

(c) 7p

(d) \(\frac{p}{7}\)

(e) (-m) -7

(f) 5 x (-p) or -5p

(g) \(\frac{-p}{5}\)

(h) -5p

Question 5.

Give expressions in the following cases.

(a) 11 added to 2m

(b) 11 subtracted from 2m

(c) 5 times y to which 3 is added

(d) 5 times y from which 3 is subtracted

(e) y is multiplied by -8

(f) y is multiplied by -8 and then 5 is added to the result

(g) y is multiplied by 5 and the result is subtracted from 16

(h) y is multiplied by -5 and the result is added to 16.

Solution:

(a) 2m + 11

(b) 2m – 11

(c) (5xy) + 3 = 5y + 3

(d) (5 x y) – 3 = 5y – 3

(e) y x (-8) = -8y

(f) [y x (-8)] + 5 = -8y + 5

(g) 16 – (y x 5) = 16 – 5y

(h) 16 + [y x (-5)] = 16 + (-5y)

Question 6.

(a) Form expressions using t and 4. Use not more than one number operation. Every expression must have t in it.

(b) Form expressions using y, 2, and 7. Every expression must have in it. Use only two number operations. These should be different.

Solution:

(a) We can have the following expressions:

t + 4, t – 4, 4t, \(\frac{t}{4}\) , 4 – t…

(b) 2y + 7, 2y – 7, 7y + 2, 7y – 2…