Gujarat Board GSEB Textbook Solutions Class 7 Maths Chapter 9 Rational Numbers InText Questions and Answers.
Gujarat Board Textbook Solutions Class 7 Maths Chapter 9 Rational Numbers InText Questions
Try These (Page 174)
Question 1.
Is the number \frac { 2 }{ -3 } rational? Think about it.
Solution:
Yes, \frac { 2 }{ -3 } is a rational number,
∵ 2 and – 3 are integers and – 3 ≠ 0.
Question 2.
List ten rational numbers.
Solution:
Following are ten rational numbers:
\frac { 1 }{ 3 }, \frac { 2 }{ -3 }, \frac { 4 }{ 5 }, \frac { 1 }{ -6 }, \frac { -3 }{ – 4 } 5.8, 2\frac { 4 }{ 5 }, 0.93, 18 and 11.07.
Note.
1. ‘0’ can be written as \frac { 0 }{ 2 } or \frac { 0 }{ 15 }, etc. Hence, it is a rational number.
2. A natural number can be written as 5 = \frac { 5 }{ 1 } or 108
= \frac { 108 }{ 1 }
Hence, it is also a rational number.
Try These (Page 175)
Question 1.
Fill in the boxes:
Solution:
Try These (Page 175)
Question 1.
Is 5 a positive rational number?
Solution:
Yes, 5 or \frac { 5 }{ 1 } is having both its numerator and denominator as positive.
∴ It is a positive rational number.
Question 2.
List five more positive rational numbers.
Solution:
\frac { 1 }{ 7 }, \frac { 3 }{ 8 }, \frac { 5 }{ 17 }, \frac { 2 }{ 9 } and \frac { 5 }{ 18 } are positive rational numbers.
Try These (Page 176)
Question 1.
Is – 8 a negative rational number?
Solution:
Yes, – 8 or \frac { -8 }{ 1 } is a negative rational number, because its numerator is a negative integer.
Question 2.
List five more negative rational numbers.
Solution:
Five negative rational numbers are as follows:
\frac { – 5 }{ 9 }, \frac { -6 }{ 11 }, \frac { -3 }{ 13 }, \frac { 3 }{ -10 } and \frac { -1 }{ 7 }
Try These (Page 176)
Question 1.
Which of these are negative rational numbers?
(i) \frac { -2 }{ 3 }
(ii) \frac { 5 }{ 7 }
(iii) \frac { 3 }{ -5 }
(iv) 0
(v) \frac { 6 }{ 11 }
(vi) \frac { -2 }{ -9 }
Solution:
(i) \frac { -2 }{ 3 } is a negative rational number.
(ii) \frac { 5 }{ 7 } is a positive rational number.
(iii) \frac { 3 }{ -5 } is a negative rational number.
(iv) 0 is neither a positive nor a negative rational number.
(v) \frac { 6 }{ 11 } is a positive rational number.
(vi) \frac { -2 }{ -9 } is a positive rational number.
∴ (i) \frac { -2 }{ 3 } and (ii) \frac { 3 }{ -5 } are negative rational numbers.
Try These (Page 178)
Question 1.
Find the standard form of:
(i) \frac { -18 }{ 45 }
(ii) \frac { -12 }{ 18 }
Solution:
(i) Since HCF of 18 and 45 is 9.
∴ \frac { -18 }{ 45 } = \frac { (-18)÷9 }{ 45÷9 } = \frac { -2 }{ 5 }
Thus, the standard form of is \frac { -18 }{ 45 } is \frac { -2 }{ 5 }
(ii) Since, HCF of 12 and 18 is 6.
∴ \frac { -12 }{ 18 } = \frac { (-12)÷6 }{ 18÷6 } = \frac { -2 }{ 3 }
Thus, the standard form of \frac { -12 }{ 18 } is \frac { -2 }{ 3 }
Try These (Page 181)
Question 1.
Find five rational numbers between \frac { -5 }{ 7 } and \frac { -3 }{ 8 }.
Solution:
First we convert the given rational numbers with common denominators.
∵ LCM of 7 and 8 is 56.
Thus, the five rational numbers, between \frac { -5 }{ 7 } and \frac { -3 }{ 8 } are:
\frac { -39 }{ 56 }, \frac { -38 }{ 56 }, \frac { -37 }{ 56 }, \frac { -36 }{ 56 }, \frac { -35 }{ 56 }
or \frac { -39 }{ 56 }, \frac { -19 }{ 28 }, \frac { -37 }{ 56 }, \frac { -9 }{ 14 }, \frac { -5 }{ 8 }
Try These (Page 185)
Question 1.
Find:
(i) \frac { -13 }{ 7 } + \frac { 6 }{ 7 }
(ii) \frac { 19 }{ 5 } + \frac { -7 }{ 5 }
Solution:
Question 2.
Find:
(i) \frac { -3 }{ 7 } + \frac { 2 }{ 3 }
(ii) \frac { -5 }{ 6 } + \frac { -3 }{ 11 }
Solution:
(i) \frac { -3 }{ 7 } + \frac { 2 }{ 3 }
∵ LCM of 7 and 3 is 21.
∴ \frac { -3 }{ 7 } = \frac { (-3)×3 }{ 7×3 } = \frac { -9 }{ 21 }
and \frac { 2 }{ 3 } = \frac { 2×7 }{ 3×7 } = \frac { 14 }{ 21 }
∴ \frac { -3 }{ 7 } + \frac { 2 }{ 3 } = \frac { -9 }{ 21 } + \frac { 14 }{ 21 }
= \frac { -9+14 }{ 21 }
= \frac { 5 }{ 21 }
(ii) \frac { -5 }{ 6 } + \frac { -3 }{ 11 }
Since, LCM of 6 and 11 is 66.
Try These (Page 186)
Question 1.
What will be the additive inverse of \frac { -3 }{ 9 }? \frac { -9 }{ 11 }?\frac { 5 }{ 7 }?
Solution:
Additive inverse of \frac { -3 }{ 9 } is \frac { 3 }{ 9 }
Additive inverse of \frac { -9 }{ 11 } is \frac { 9 }{ 11 }
Additive inverse of \frac { 5 }{ 7 } is \frac { -5 }{ 7 }
Try These (Page 187)
Question 1.
Find:
(i) \frac { 7 }{ 9 } – \frac { 2 }{ 5 }
(ii) 2\frac { 1 }{ 5 } – \frac { -1 }{ 3 }
Solution:
Try These (Page 188)
Question 1.
What will be
(i) \frac { -3 }{ 5 } x 7?
(ii) \frac { -6 }{ 5 } x (-2)?
Solution:
(i) \frac { -3 }{ 5 } x 7 = \frac { (-3)×7 }{ 5 } = \frac { -21 }{ 5 }
(ii) \frac { -6 }{ 5 } x (-2) = \frac { -6×(-2) }{ 5 } = \frac { 12 }{ 5 }
Note:
We multiply two rational numbers in the following way:
(i) Multiply the numerators of the rational numbers.
(ii) Multiply the denominators of the rational numbers.
(iii) Then product =
For example:
Try These (Page 188)
Question 1.
Find:
(i) \frac { -3 }{ 4 } x \frac { 1 }{ 7 }
(ii) \frac { 2 }{ 3 } x \frac { -5 }{ 9 }
Solution:
Try These (Page 189)
Question 1.
What will be the reciprocal of \frac { -6 }{ 11 } and \frac { -8 }{ 5 }?
Solution:
(i) Reciprocal of \frac { -6 }{ 11 } is \frac { 11 }{ -6 }
(ii) Reciprocal of \frac { -8 }{ 5 } is \frac { -5 }{ 8 }.
To divide one rational number by the other rational number, we multiply the rational number by the reciprocal of the other. For example,
Try These (Page 190)
Question 1.
Find:
(i) \frac { 2 }{ 3 } x \frac { -7 }{ 8 }
(ii) \frac { -6 }{ 7 } x \frac { 5 }{ 7 }
Solution: